three cubes of side 3 cm 4 cm and 5 cm are melted and a new cube is formed find the edge of the new cube
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37
Given
We melt 3 cubes of side 3cm, 4cm, 5cm
Volume of cube =a³
After melt the cube the total volume we
=3³+4³+5³=27+64+125=216cm³
The sum of volume of all three cubes = volume of new cube
Sum of volume 216cm³
So volume of new cube =216cm³
Side =A
A³=216cm³
a = \sqrt[3]{216}a=3216
A=6cm
This is ur ans hope it will help you in case of any doubt comment below
We melt 3 cubes of side 3cm, 4cm, 5cm
Volume of cube =a³
After melt the cube the total volume we
=3³+4³+5³=27+64+125=216cm³
The sum of volume of all three cubes = volume of new cube
Sum of volume 216cm³
So volume of new cube =216cm³
Side =A
A³=216cm³
a = \sqrt[3]{216}a=3216
A=6cm
This is ur ans hope it will help you in case of any doubt comment below
Answered by
28
Volume of the new cube = volume of three cubes
(A)³ = a³+a³+a³
A³ = (3)³+(4)³+(5)³
A³ = 27+64+125
A³ = 216
=> A = 6 cm
Therefore, the edge of new cube is 6 cm.
HOPE IT HELPS YOU !!!!
(A)³ = a³+a³+a³
A³ = (3)³+(4)³+(5)³
A³ = 27+64+125
A³ = 216
=> A = 6 cm
Therefore, the edge of new cube is 6 cm.
HOPE IT HELPS YOU !!!!
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