Question

three cubes whose edges are 6cm,8cm and 10 cm,respectively,are melted without any loss of metal into a single cube.Find the edge of the new cube​

Answer 1

Step-by-step explanation:

volume of cube

$6 {}^{3} = 216 \\ {8}^{3} = 512 \\ {10}^{3} = 1000$

so,

new cube =216+512+1000

=1728

hence

the edge of new cube=

$\sqrt[3]{1728} = 12$

I hope it will be helpful

Answer 2

The edge of new cube is 12 cm

Step-by-step explanation:

Given: Three cubes of edge 6 cm , 8 cm and 10 cm is melted and recast a new cube

To find: The edge of new cube

As we know the volume of cube is given by

Volume = a³ where a is the length of edge

Therefore

the volume of cube having edge length  6 cm is

$V_1= 6^3= 216cm^3$

the volume of cube having edge length  8 cm is

$V_2=8^3= 512 cm^3$

the volume of cube having edge length  10 cm is

$V_3=10^3= 1000cm^3$

Now the total volume is

V= 216 cm³+512 cm³+1000 cm³

V= 1728 cm³

Now

Let x is the edge of new cube

$\therefore\\V=x^3\\\\\Rightarrow 1728= x^3\\\\\Rightarrow \sqrt[3]{1728} =x\\\\\Rightarrow x=12 cm$

Hence the edge of new cube is 12 cm

#Learn more

The metal cubes if side 5cm ,4cm and 3cm are melted an recast into a cube .find edge of new cube so formed.

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