Question

Three dice are rolled. The number of possible outcomes in which at least one die shows 6 is

Answer 1

Answer:

11

Step-by-step explanation:

# outcomes with at least one 6

= ( # outcomes die 1 shows 6 ) + ( # outcomes die 2 shows 6 ) - ( # outcomes both dice show 6 )

( we need to subtract the last term since that has been counted twice when adding the other two... this is the Principle of Inclusion-Exclusion)

= 6 + 6 - 1

= 11

Answer 2

Answer:

When a single unbiased die is thrown you can have six possible outcomes. Similarly, when three dice are thrown simultaneously, the total number of outcomes will be 6*6*6=216

Step-by-step explanation: