Question

(x-7)(x-9)=195 ..........quadratic eq

Answer 1

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(x-7)(x-9)=195
x^2 -9x-7x+63-195=0
x^2-16x-132=0
x^2-22x+6x-132=0
x(x-22)+6(x-22)=0
(x+6)(x-22)=0
x= -6 OR x=22

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Answer 2

(x-7)(x-9)=195
x(x-9)-7(x-9)=195
x^2-9x-7x+63=195
x^2-16x+63-195=0
x^2-16x-132=0
by factorisation method,
sum,s= -16(-22+6)
product, p= -132( -22×6)
x^2-22x+6x-132=0
x(x-22)+6(x-22)=0
(x-22)(x+6)=0
x=22 or x= -6 is the answer
Hope you got it.