Three dice are rolled what is the probability of getting same no. On three of them
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It's just (16)2 It's the probability that the second roll is the same as the first (1/6) multiplied by the probability that the third roll is the same as the second (1/6).
Or, think of it this way. The desired outcomes are (1,1,1), (2,2,2), ... ,(6,6,6). Each of these outcomes has probability (16)3. Sum these the probabilities of these mutually exclusive outcomes to get 6⋅(16)3=(16)2.
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