Question

three dice are thrown together.find the probability of getting total value of atleast 6
give me the reason​

Answer 1

Answer:

103/108

Step-by-step explanation:

There are 6 possible values for each dice, so the total number of events is 6^3 = 216

P=1-P when looking at P(sum < 6)

There are ten events in which the outcome is less than 6: (1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)

So, P (sum < 6) = 10/216

P (sum > 6) = 1-(10/216) = 103/108