Math, asked by NININP4250, 10 months ago

Three dice are thrown together.Find the probability of getting a total of atleast 6.

A) 103/216 B) 103/108 C) 103/36 D) 36/103

Answers

Answered by TheChessKing
1

Answer:

A) 103/216

Step-by-step explanation:

(vi) getting a total of at least 6. Solution: Three different dice are thrown at the same time. Therefore, total number of possible outcomes will be 63 = (6 × 6 × 6) = 216.

i hope it helps u

Answered by Anonymous
1

Answer :

a)103/216

Explanation :

The formula for finding probability is

= No. of favourable outcomes

__________________________

No . of possible outcomes

Here favourable outcomes will be 103 and possible outcomes is 216

(6×6×6 = 216)

Hope it helps :)

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