Question

Three dice are thrown togetyer.Find the probability of geting a total of atleast 6

Answer 1

Answer:

P = (103/108)

Step-by-step explanation:

Dear,

Here is your answer.

•Number of possibility =6^3 = 6×6×6 =216

•Number of events of getting a total of atmost 5 = 10 events.

(1, 1, 1), (1, 1, 2), (1, 2, 1), (2, 1, 1), (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1) and (1, 2, 2).

#(We doesn't count for atleast 6. If we count for it, it's have too many events

So we need to count for almost 5 then we subtract it from 1 so we will get our answer.)#

∆. P' = (10/216)

∆. P' = (5/108)

•So P = 1 - P'

∆. P= 1-(5/108)

∆. P = (103/108) Ans...

Hope it's help you.

Thank-you..