three dice is thrown simultaneously .the probability of getting a sum of 15 is
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Answer:
206/216
Step-by-step explanation:
Assuming we are talking 3d6, which is to say 3 fair dice cubes each labeled 1 thru 6
There are 6*6*6=216 possible combinations
Of these 1 is an 18, 3 are 17, 6 are 16. 1+3+6=10 combinations that are over 15.
216–6=206
So the odds of getting no more than 15 are 206/216
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