Question

Three dices are rolled. what is the probability that their product is divisible by two

Answer 1

Answer:

72 may be i am not sure about my ans

Answer 2

$\fontsize{18}{10}{\textup{\textbf{The required probability is 0.75.}}}$

Step-by-step explanation:  

When two dice are rolled, then the sample space of the experiment is given by

S = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1), (2, 2), (2, 3),  .   .   .   , (6, 5), (6, 6)}.

Let E be the event that the product is divisible by 2.

Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}.

So, n(S) = 36  and  n(E) = 27.

Therefore, the probability of event E is given by

$P(E)=\dfrac{n(E)}{n(S)}=\dfrac{27}{36}=\dfrac{3}{4}=0.75.$

Thus, the required probability is 0.75.

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