Question

three different coins are tossed together. find the probablity of getting 1 exactly two heads 2 atleast two heads 3 atleast two tails ​

Answer 1

Step-by-step explanation:

number of outcomes = 4 i.e(HH),(TT)(,(HT),(TH)

1) P(HH)=1/4

2)P(HH)=1/4

4)P(TT)=1/4

Answer 2

P(getting exactly two heads)=3/8

P(getting atleast two head) =4/8=1 /2

P(getting atleast two tail )=4/8=1/2

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