three differeny tankers contains 496 liters,403 liters and 713 liters of milk find the maximum capacity of a container that can measure the milk of any tanker on exact if times
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max. capacity of container=HCF(496,403,713)
496=403*1+93
403=93*4+31
93=31*3+0
∴HCF(496,403)=31
713=31*23+0
∴HCF(496,403,713)=max. capacity of container=31 litres
i hope this helps!!
496=403*1+93
403=93*4+31
93=31*3+0
∴HCF(496,403)=31
713=31*23+0
∴HCF(496,403,713)=max. capacity of container=31 litres
i hope this helps!!
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