Math, asked by domnick7275, 10 months ago

three-digit number the digit at its hundred's place is
two times the digit at the unit's place and the sum of
the digits is 18. If the digits are reversed, the number
is reduced by 396. The difference of hundred's and
ten's digit of the number is?​

Answers

Answered by Nihaldan16
1

answer is 2 ..................................................

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domnick7275: worng answer try again bro
Answered by Sleepingpanda
0

Let the digit at unit's place be x

Digit at hundred's place is 2x

Let the digit at tens place be y

So, x+3x+y=18

Or,4x +y=18

Also, 100x3x +10y+x= 100x +10y +3x +396

OR, 301x +10y =103x +10y +396

Or, 301x - 103x =396

Or, 198x= 396

Or, x=2

Putting x=2 in 1st equation,

8+y=18

Or,y=10.

So the digits are, 2,10 and 6 at unit, tens and hundreds place.

Difference between hundred and tens place digit is

10-6=4.


domnick7275: worng answer try again bro
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