Question

Three dimensions of cuboid are 44 cm 21 cm 12 cm it is melted and a cone of height 24 cm is made find the radius of its base

Answer 1

here is your answer.....
_________________
volume of cubiod = 44cm×21cm×12cm

= 11088 cm^3

height of cone formed = 24cm

A/Q.
the volume of cone = 11088cm^3

$==> \: \frac{1}{3} \times \pi \times {r}^{2} \times h = 11088 {cm}^{3} \\ ==> \frac{1}{3} \times {r}^{2} \times 24cm = 11088 {cm}^{3} \\ == > {r}^{2} = \frac{11088 {cm}^{3} \times 3 }{24cm} \\ ==> {r}^{2} = 1386 {cm}^{2} \\ ==>r = \sqrt{1386 {cm}^{2} } \\ ==> r = 37.229cm$
therefore, radius of its base = 37.229 cm
,i.e., = 37.23cm

hope this helps.......


with regards..
☆Misa

Answer 2

please mark as brainlist answer follow me Mark