Question

Three eggs are drawn at random without replacement from a bag containing two bad eggs
and eight good eggs. Find the probability of getting two bad eggs.
19
பகுதி - II / PART -II
மப்பாக​

Answer 1

Step-by-step explanation:

number of good eggs-8

number of bad eggs-2

Answer 2

The probability of getting two bad eggs is 0.022 or 2.2%

Step-by-step explanation:

Number of good eggs = 8

Number of bad eggs = 2

Total number of eggs = 8 + 2 = 10

Probability of getting bad egg on first drawn $P_{1}=\frac{2}{10}$

After first drawn (without replacement) number of bad egg = 1

and total eggs remained 9.

Probability of getting bad egg on second drawn $P_{2} =\frac{1}{9}$

$P=P_{1}\times P_{2}$

   $=\frac{2}{10} \times \frac{1}{9}$

   $=\frac{1}{45}$

   = 0.022 or 2.2%

The probability of getting two bad eggs is 0.022 or 2.2%.

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