three electric bulbs of 200w,200wand 400w are shown in the fig. the resultant ppwer of combination is
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hello dear friends ^-^
option (c) is correct..
Dear Student
When the bulbs are connected in parallel, each bulb has V across it, each draws 100/V A, and each dissipates 100 watts. Both bulbs glow at their full brightness. The total power dissipated across these two bulbs is two times 100, or 200 watts (or 2(100/V) A × V = 200 W).
hope its help uh!!!
option (c) is correct..
Dear Student
When the bulbs are connected in parallel, each bulb has V across it, each draws 100/V A, and each dissipates 100 watts. Both bulbs glow at their full brightness. The total power dissipated across these two bulbs is two times 100, or 200 watts (or 2(100/V) A × V = 200 W).
hope its help uh!!!
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