Question

Prove that sin34°/sin 56° + cos 34°/cos 56° = sec 34°.cosec 34°

Answer 1

hey dear friends [^^_^^]


solution=>
Use,
sin(34) = sin(90-56) = cos(56)
similarly,. cos(34) = cos(90-56)= sin(56)
now put the above obtained values of numerater in question.
cos(56)/sin(56) + sin(56)/cos(56)
now take LCM,
=cos^2(56)+sin^2(56)/sin(56)cos(56)
=1/sin(56)cos(56)
= 1/cos(34)sin(34). sin(56)=sin(90-34)=cos(34)
= sec34 . cosec 34

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hope its help uh.......


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$Sumit Tiwari from Azamgarh (up)$

Answer 2

I hope it helps the answer for you