Question

Three electronic devices beep at every 24, 36 and 48 seconds respectively. If they beep together at 10:30 a.m. then what is the earliest time at which they beep together? Pls don't give answer from another site
or I will report. Pls give solved solution​

Answer 1

Answer:

Required LCM = 24,36,48 sec

By doing LCM of 24,36,48 we get

LCM=2×2×2×2×3×3=144

Required sec is 96 .

and tge earliest time at which they keep together is 10: 96sec.

Hope it helps u mate

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Answer 2

Answer:

Given : Three electronic devices make a beep after every 48 sec, 72 sec and 108 sec respectively.

To find : They beeped together at 10  a.m. the time when they will next make a beep together at the earliest is?

Solution :

First we find the least common multiple of the three electronic devices.

LCM of 48,72,108 is

The least common multiple of 48,72,108 is 432 seconds.

Converting seconds into minutes

They beeped together at 10  a.m.

They will next make a beep together at the earliest is 10:07:02 am.

i.e. After 10 o'clock 7 minutes and 2 seconds it beep.