Question

Three forces 10N 20N 40N acting along sides AB BC AC of equilateral triangle ABC find magnitude of resultant

Answer 1

Answer:

Magnitude of resultant = 10√3

Explanation:

Forces A,B,C are 30N,20N,10N respectively.

Let force A act along+ve x-axis then Force A = 30i

Force B = (20cos120°)i + (20sin120°)j

Force C= (10cos240°)i +(10sin240°)j

So, Force A = 30i Force ,B= -10i +10√3j,Force C= -5i -5√3j