Question

Three forces that act on a particle are given by f1=(20i-36j+73k)N,f2=(-17i+21j-46k)N and f3=(-12k)N.find their resultant vector and magnitude

Answer 1

F1 = 20 i - 36 j + 73 k

F2 = -17i + 21 j - 46 k

F3 = -12 k

By the principle of superposition,

Fnet = F1 + F2 + F3

= 3 i - 15 j + 15 k

This will be the resultant vector of Net force.

Magntiude of this resultant force = √225 + 225 + 9 = √ 459 Netwons