Question

Three friends, a, b and c have houses along a straight road, in that order. If all three want to meet up at one of their houses, what is the minimum combined distance they need to travel? The distance between a’s house and b’s house is 2 miles. The distance between a’s house and c’s house is 8 miles

Answer 1

Total=Apartment+P.homes

=5+3

so Brick made=3+5(1-9/10)=75/10

so the portion is=(75/10)/8=75/80=15/16