Three friends A,B,C ate at restaurant and bill was rupeees 30 .A paid one half of theamount paid by B andC.C paid one fifth of amount paid by A and B.Then B paid
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A=1/2(B+C)
C=1/5(A+B)
Given A+B+C=30
Substituting A value in above equation we get
1/2(B+C)+B+C=30
3B+3C=60
B+C=20,C=20-B
Substituting above value in A
A=1/2(20)=10
Now C=1/5(A+B)=1/5(10+B)
=2+(B/5)
100-5B=10+B
6B=90
B=90/6=15
C=1/5(A+B)
Given A+B+C=30
Substituting A value in above equation we get
1/2(B+C)+B+C=30
3B+3C=60
B+C=20,C=20-B
Substituting above value in A
A=1/2(20)=10
Now C=1/5(A+B)=1/5(10+B)
=2+(B/5)
100-5B=10+B
6B=90
B=90/6=15
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