Question

Three friends plan to go for a morning walk they step off together and their steps measure 48 cm 52 cm and 56 cm respectively who is the minimum distance each should walk so that each can cover the same distance in complete step 10 times

Answer 1

Step-by-step explanation:

We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance

 Now,

 40 = 2 × 2 × 2 × 5,

 42 = 2 × 3 × 7

45 = 3 × 3 × 5

∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520

Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.

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Answer 2

Answer:

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We have to find the LCM of 40 cm, 42 cm and 45 cm to get the required minimum distance. Because we are asked the minimum distance

 Now,

 40 = 2 × 2 × 2 × 5,

 42 = 2 × 3 × 7

45 = 3 × 3 × 5

∴ LCM (40, 42, 45) = 2 × 3 × 5 × 2 × 2 × 3 × 7 = 30 × 12 × 7 = 210 × 12 = 2520

Minimum distance each should walk 2520 cm. so that, each can cover the same distance in complete steps.