Question

Three gases of densities A (0.82) B(0.25) C(0.51) are enclosed in a vessel of 4L capacity .Pick up the correct statement :( Assume ideal behaviour )
(A) Gas A will tend to lie at the bottom (B) The number of atoms of various gases A B C are same (C) The gases will diffuse to form homogenous mixture (D)The average kinetic energy of each gas is same

Answer 1

Gas A will tend to lie at the bottom and the average kinetic energy of each gas is the same.

Options (A) and (D) are correct.

Explanation:

• As per the statement of the question, the density of gas A is higher therefore it will be heavy than the other gases.
• Gas A will lie at the bottom of the vessel.
• As all the gas molecules are moving randomly and colliding with each other transferring the energy from one to another.
• Therefore all molecules will have the average kinetic energy.

Answer 2

$\huge \tt option \: \boxed{ \tt a} \: and \: \boxed{ \tt d}$