Question

three group of children content respectively a girl and one boy, two girl and two boys one girls and 3 boys, one children is selected at random from each group find the chance that the three selected consists of one girl and two boy ​

Answer 1

Answer:

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Answer 2

The probability of selecting of 1 boy from the first group is 1/4, 1 girl 3/4

The probability of selecting of 1 boy from the second group is 1/2, 1 girl 1/2

The probability of selecting of 1 boy from the third group is 3/4, 1 girl 1/4.

The probability of selecting of 1 girl and 2 boys is

P(girl from I group) AND P(boy from II group) AND P(boy from III group) OR

P(boy from I group) AND P(girl from II group) AND P(boy from III group) OR

P(boy from I group) AND P(boy from II group) AND P(girl from III group)

In Math it equals to (AND = "*", OR = "+"):

3/4*1/2*3/4 + 1/4*1/2*3/4 + 1/4*1/2*1/4 = 9/32 + 3/32 + 1/32 = 13/32