Question

Three identical bulbs P, Q and R are connected in a circuit as shown the figure. If Bulb R is removed from the circuit then

Answer 1

Answer:

We know that Power=i

2

R

bulb Q and R are in parallel to each other and combine are in series to bulb P hence the current will be distributed according to series and parallel concept of resistances.

⇒I

Q

=I

R

=

2

I

p

[∴ Q and R are identical I

Q

=I

R

]

⇒P

P

=I

P

2

×R

P

Q

=P

R

=

4

I

P

2

R

∴P

P

>P

Q

=P

R

Answer 2

Answer:

this is your answer

hope this will help you