Three identical cells of emf 2v and internal resistance 1 ohm are connected in series. Find the effective resistance of combination
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Answered by
0
Answer:
As it is series connection ,
Total R = R1 + R2 + R3
R = 1+1+1
= 3 ohms.
Answered by
0
Answer:
in series
equivalent emf=e1+e2+e3
=2+2+2=6v
equivalent internal resistance=r1+r2+r3
=1+1+1=3Ω
if external resistance is not. there hence resistance of communication=3Ω
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