Three identical charges are placed at corners of an equilateral triangle of side l . if force between any two charges is f , the work required to double the dimensions of triangle is ?
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The work done in doubling the dimensions of the above mentioned triangle is 3kq^2 / 2l J.
According to Work Energy Theorem:
Work (W) = Change in potential energy (Uf - Ui)
Initial potential energy (Ui) = kq^2 / l + kq^2 / l + kq^2 / l = 3kq^2 / l
Final potential energy (Uf) = kq^2 / 2l + kq^2 / 2l + kq^2 / 2l = 3kq^2 / 2l
Hence work done is:
W = 3kq^2 / l - 3kq^2 / 2 = 3kq^2 / 2l J
According to Work Energy Theorem:
Work (W) = Change in potential energy (Uf - Ui)
Initial potential energy (Ui) = kq^2 / l + kq^2 / l + kq^2 / l = 3kq^2 / l
Final potential energy (Uf) = kq^2 / 2l + kq^2 / 2l + kq^2 / 2l = 3kq^2 / 2l
Hence work done is:
W = 3kq^2 / l - 3kq^2 / 2 = 3kq^2 / 2l J
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