Question

Three identical equilateral triangle of side 5 cm each are placed together such a way that they form trapezium. The length of the longer of the two parallel sides of the trapezium is -------.

OPTION
$(1) \: \: \frac{3}{4} \: cm$
$(2) \: \: 5 \sqrt{2} \: cm$
$(3) \: \: 10 \: cm$
$(4) \: \: 10 \sqrt{2} \: cm$
Answer WITH rough DIAGRAM and proper EXPLANATION.

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Answer 1

$[tex](1) \: \: \frac{3}{4} \: cm$

$(2) \: \: 5 \sqrt{2} \: cm$

$(3) \: \: 10 \: cm$

$(4) \: \: 10 \sqrt{2} \: cm$[/tex]

Answer 2

Answer:

option 3

10 cm is the length of the longer of the two parallel sides of the trapezium.

Step-by-step explanation:

If 3 equilateral triangles are arranged in -

• one inverted and
• other two at erect position

(as shon in the given attachment)

The length of the longer of the two parallel sides of the trapezium is BZ

and BZ = 10 cm.