three identical particles of mass m are placed on the vertices of an equilateral triangle of side 'a'. The net gravitational force on any particle is--
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shown in the figure, when P is at the mid point of a side, →FA and →FB will be equal in magnitude but opposite in direction. Hence they will cancel each other. So the net force on the particle P will be the force due to the particle placed at C only. ⇒F=FC=cm
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