Question

Three identical point charges of q coulomb are placed at the vertices of an equilateral triangle, 10cm apart. Calculate the magnitude of the force on each charge.

Answer 1

Magnitude of force = kq^2 ×√3

Force between two point charges is given by kq1 q2/ r^2

Where k= 9×10^9

q1 is the charge number one

q2 is the charge number two

And r is the distance between two charges

Here force between two charge is kqq/(10)^2

And angle between the two pair is 60°

Therefore answer is √3× kqq/100

100cm=1m

Therefore, √3×kqq