Three identical resistors each of resistance R are connected to an ideal cellof voltage V as shown. Total power dissipated in all three resistors is :
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Answer:
take put the parallel resistance and add simply as it will become a series circuit then calculate power
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Explanation:
HEY MATE
HERE IS YOUR ANSWER
1/REQ = 1/R+1/R
1/REQ1=2/R
REQ1=R/2
ALSO IN SERIES
R/2+R=3R/2
VOLTAGE=V
REQ =3R/2
AS POWER DESSIPETED
IS
P=V²/R
P=2V²/3R
SO TOTAL POWER DESSIPETED IS 2V²/3R
HOW HELP YOU
THANKS
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