Chemistry, asked by btchface739, 11 months ago

three liquids are given one is hydrochloric acid ; another is sugar solution and third is Sodium Hydroxide how will you identify them you have only turmeric indicator ?​

Answers

Answered by ZiaAzhar89
32

\mathbb{\huge{\purple{Zia\: Dilliwali}}}

From NCERT

Turmeric will turn pinky-red in alkali, but is yellowish in both acid and neutral solutions. 

So test some of your three solutions with turmeric, and the one that turns the indicator pink is the sodium hydroxide solution. 

Now that you know which is NaOH, mix some of thi, separately with some of the other two solutions. The one that gets warmer is the HCl - the neutralisation of HCl with NaOH is exothermic. There is no (rapid) reaction of sugar solution with NaOH so it shouldn't change temperature by much.


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Answered by prasnshpc
45

Answer:

Take small amount of the liquids and add turmeric indicator. The solution which gives red colour with turmeric is sodium hydroxide. Now add small amount of the remaining solutions to water. The solution which becomes warm on adding water is hydrochloric acid and the third liquid is sugar solution.

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