Physics, asked by ms562053, 4 days ago

Three magnetically coupled inductive coils having the following data are connected in series as shown in Figure. L1 = 0.12 H; L2 = 0.14 H; L3 = 0.16 H k12 = 0.3; k23 = 0.6; k31 = 0.9 Find the equivalent inductance of the circuit.​

Answers

Answered by lalitmandrai
0

Answer:

L1, L2 and L3 connected in series,

0.12 + 0.14 + 0.16 = 0.42 H

Mutual Inductance

m1 \:  =  \: 0.0388844442 \: H

m3 \:  =  \: 0.1247076581 \: H

m2 \:  = 0.0897997773 \: H

Equivalent Mutual Inductance

m \: eq = 0.2533918796 \:  henry

For all the adding mutual Inductance

For all the adding mutual InductanceLeq,

0.42 + 0.25339 = 0.6733918796 \: henry

For all the opposing mutual Inductance

For all the opposing mutual InductanceLeq,

0.42−0.25339 = 0.1666081204 \: henry

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