Question

Three marketers distribute their products in a colony for pilot testing. Market A distributes 150 items to the people equally and then was left with a few items. marketer b distributes 270 items to the people equally and the was left with the same number of items as the number left with marketer A. Marketer c distributes 320 items to the people and is left with the same number of items as the number left with market A. what is the maximum possible number of people in the colony?

Answer 1

Answer:

The maximum possible number of people in the colony is the highest common factors among 150, 270 and 320 which is 10.

Step-by-step explanation:

Prime factors of 150 = 2×3×5×5

Prime factors of 270 = 2×3×3×3×5

Prime factors of 320 = 2×2×2×2×2×2×5

Common factors = 2×5

HCF = 10  (Answer)

Answer 2

Answer: There are maximum 10 number of people in the colony.

Step-by-step explanation:

Since we have given that

Number of items distributed by market A = 150

Number of items distributed by market B = 270

Number of items distributed by market C = 320

We need to find the maximum possible number of people in the colony.

So, Maximum possible number of people = H.C.F. of 150, 270, and 320.

so, H.C.F. = 10

Hence, there are maximum 10 number of people in the colony.