Question

three masses 3,4,5 kg are located at the corner of an equilateral triangle of side 1 m. locate the centre of mass of system

Answer 1

Let the point O be the origin that is, O =(0,0), A = (1,0) 
so,B = (0.5, 0.866) 
[As OAB is an equilateral triangle] 
X-coordinate of the center of mass, X = (0*3 + 1*4 + 0.5*5)/(5+4+3) 
= 6.5/12 = 0.54 m 
Y- Coordinate of the center of mass, Y = 0*3 + 0*4 + 0.866*5/12 
= 0.36 m 
Center of mass of the system, (X, Y) = (0.54m, 0.36m) 



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Answer 2

Explanation:

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