Question

Three masses 3 kg, 4 kg and 5 kg are located at the corners of an equilateral triangle of side 1m. Locate the centre of mass of the system

Answer 1

Let the point O be the origin that is, O =(0,0), A = (1,0) 
so,B = (0.5, 0.866) 
[As OAB is an equilateral triangle] 
X-coordinate of the center of mass, X = (0*3 + 1*4 + 0.5*5)/(5+4+3) 
= 6.5/12 = 0.54 m 
Y- Coordinate of the center of mass, Y = 0*3 + 0*4 + 0.866*5/12 
= 0.36 m 
Center of mass of the system, (X, Y) = (0.54m, 0.36m)