Three masses 3 kg, 4 kg and 5 kg are located at the corners of an equilateral triangle of side 1m. Locate the centre of mass of the system
Answers
Answered by
8
Let the point O be the origin that is, O =(0,0), A = (1,0)
so,B = (0.5, 0.866)
[As OAB is an equilateral triangle]
X-coordinate of the center of mass, X = (0*3 + 1*4 + 0.5*5)/(5+4+3)
= 6.5/12 = 0.54 m
Y- Coordinate of the center of mass, Y = 0*3 + 0*4 + 0.866*5/12
= 0.36 m
Center of mass of the system, (X, Y) = (0.54m, 0.36m)
Similar questions
Hindi,
7 months ago
Accountancy,
7 months ago
Science,
7 months ago
Accountancy,
1 year ago
History,
1 year ago
Science,
1 year ago
Math,
1 year ago