Question

three masses of 16 kg 8 kg 4 kg are placed in contact are in fig if a force of 140N is applied on 4kg mass then the force on 4 kg mass then the force on 16 kg will be 1) 140n 2)120N 3)100N 4)80 N​

Answer 1

Answer:

Explanation:

If masses are m1,m2&m3 and force be f

Then,

force on m1=(m1*f)/(m1+m2+m3)

             Consider m1= 16 kg

Then,

Force on 16 kg

             =16*140/(16+8+4)

             =16*140/28

             =80 N