Three men or 5 women can finish a work in 43 days. How would one day end five men and 6 women?
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4 women are equal to 3 men
5 women are equal to (3/4)*5 = 15/4 men.
7 men and 5 women are equal to 7 + (15/4) = 43/4 men
The ratio of 3 and 43/4 is 3 *4/ 43= 12/43
The days will change 12/43 times the initial days.
That is the days are 43*12/43 = 12 days .
hope you like it please please please please please mark has brainliest answer
5 women are equal to (3/4)*5 = 15/4 men.
7 men and 5 women are equal to 7 + (15/4) = 43/4 men
The ratio of 3 and 43/4 is 3 *4/ 43= 12/43
The days will change 12/43 times the initial days.
That is the days are 43*12/43 = 12 days .
hope you like it please please please please please mark has brainliest answer
Answered by
1
hey.....mate
your answer....
4 women are equal to 3 men
5 women are equal to (3/4)*5=14/4
7 men and 5 women are equal to 7 + (15/4) = 43/4 men
the ratio of 3 and (43/4) is 3*4/43=12/43
the days will change 12/43 times the initial days
that is the day are 43*12/43 = 12 days
hope.....it's help you
your answer....
4 women are equal to 3 men
5 women are equal to (3/4)*5=14/4
7 men and 5 women are equal to 7 + (15/4) = 43/4 men
the ratio of 3 and (43/4) is 3*4/43=12/43
the days will change 12/43 times the initial days
that is the day are 43*12/43 = 12 days
hope.....it's help you
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