Question

Three metal shot puts of radii 6cm , 8 cm and 10cm are melted to form a single shot put find the radius of the shot put obtained

Answer 1

Answer:

41.56 is 5he answer i think

Answer 2

The radius of the shot put obtained is 12 cm.

Step-by-step explanation:

Given : Three metal shot puts of radii 6 cm , 8 cm and 10 cm are melted to form a single shot put.

To find : The radius of the shot put obtained ?

Solution :

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Volume of one metal shot puts of radii 6 cm is

$V_1=\frac{4}{3}\pi (6)^3$

Volume of second metal shot puts of radii 8 cm is

$V_2=\frac{4}{3}\pi (8)^3$

Volume of third metal shot puts of radii 10 cm is

$V_3=\frac{4}{3}\pi (10)^3$

Three metal shot puts are melted to form a single shot put.

Volume of three metal shot puts = Volume of single shot put

$\frac{4}{3}\pi (6)^3+\frac{4}{3}\pi (8)^3+\frac{4}{3}\pi (10)^3=\frac{4}{3}\pi r^3$

$\frac{4}{3}\pi ((6)^3+(8)^3+(10)^3)=\frac{4}{3}\pi r^3$

$216+512+1000=r^3$

$1728=r^3$

$r=\sqrt[3]{1728}$

$r=12$

Therefore, the radius of the shot put obtained is 12 cm.

#Learn more

A shot put is a metallic sphere of radius 4.9 cm if the density of the metal is 7.8g per cm find the mass of the shot put

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