three metallic cube of side 3cm,4cm5,cm respectively are melted and ate recaste into a single cube. find the total surface area of the new cube
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The volume of the three cubes
v = (3 x 3 x 3) + (4 x 4 x 4) + (5 x 5 x 5)
= 27 + 64 + 125
= 216
Side of new cube formed by melting above 3 cubes = cube root of 216 = 6 cm
The surface area of new cube = 6 x (6 x 6) = 216 sq sm
v = (3 x 3 x 3) + (4 x 4 x 4) + (5 x 5 x 5)
= 27 + 64 + 125
= 216
Side of new cube formed by melting above 3 cubes = cube root of 216 = 6 cm
The surface area of new cube = 6 x (6 x 6) = 216 sq sm
raviseth2000:
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Hi ,
Let a = 3cm , b = 4cm , c = 5cm
are the sides of three metallic cubes ,
melted and cast into a new cube
whose side is ' d ' cm
Volume of the new cube = volumes
of the three cubes
d³ = a³ + b³ + c³
= 3³ + 4³ + 5³
= 27 + 64 + 125
= 216
d³ = 6³
d = 6 cm
Therefore ,
Total surface area of the new cube
= 6d²
= 6 × 6²
= 216 cm²
I hope this helps you.
: )
Let a = 3cm , b = 4cm , c = 5cm
are the sides of three metallic cubes ,
melted and cast into a new cube
whose side is ' d ' cm
Volume of the new cube = volumes
of the three cubes
d³ = a³ + b³ + c³
= 3³ + 4³ + 5³
= 27 + 64 + 125
= 216
d³ = 6³
d = 6 cm
Therefore ,
Total surface area of the new cube
= 6d²
= 6 × 6²
= 216 cm²
I hope this helps you.
: )
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