Chemistry, asked by BrownSwan9636, 10 months ago

Three mixtures A, B and C are obtained by stirring three different solids in water taken in separate beakers. When mixture A is allowed to stand for some time, then its particles settle at the bottom of the beaker. When a beam of light is passed thorugh mixture A in a dark room, the path of light becomes visible when observed from the side of the beaker. When mixture B is allowed to stand for a considerable time, even then its particles do not settle down. Mixture B, however, scatters the beam of light just like mixture A. The particles of mixture C do not settle down on keeping and it also does not scatter a beam of light passing throught it. [ ] i) Mixture A is suspension ii) Mixture B is a colloid iii) Mixture C is a suspension iv) Mixture A & C shows Tyndall effect What's the correct statement in these? (×÷×)人 please help me with this

Answers

Answered by srijal05trhakur
2

Answer:

(a) Suspensions (b) colloids ( c) true solutions (d) tyndall effect ( e) (i) chalk - water mixture (ii) soap solution ( c) salt solution

Explanation:

Answered by smartbrainz
0

Mixture B is colloidal in nature because of the size of the solute particles

Option b

Explanation:

  • There are different types of solution based on the size of the solute particles. As a result of this it is widely classified into pure substance colloid suspension. in case of pure substance the solute particles are smallest in nature. As a result of this there is laser diffraction of light by the solute particles which is present in the solvent.
  • tyndall effect is usually shown by the colloidal substances due to the bigger solute particles

To know more,

a solution containing 13.5 gram urea per 500 ml of solution in water ..

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