Question

Three moles of an ideal gas have an initial temperature of

127.0°C, while the temperatures are kept constant; the volume

is increased until the pressure drops to 40% of its original

value. Calculate the work done by the gas. [R = 8.36 Jmol-1K​

Answer 1

Answer:

9192.2 Joules

Explanation:

Work done by the gas is defined as ∫PdV

Since PV=nRT, we can write P=nRT/V

thus, W = ∫nRTdV/V

since n, R are constant, and T is given to be constant in the question,

W = nRT∫dV/V

   =nRT*ln(V2/V1)  ...........(integration formula)

   =nRT*ln(P1/P2)  ............(V =nRT/P)

=3*8.36*400*ln(100/40) .........(127°C = 400 K)

=9192.2 J