Three moles of B₂H₆ are completely reacted with methanol. The number of moles of boron containing product formed is
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Explanation:
Hence, three moles of diborane reacts with 18 moles of methanol to form 6 moles of boron containing product.
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Hence, three moles of diborane reacts with 18 moles of methanol to form 6 moles of boron containing product
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