Three monkeys are climbing upstairs.They can only move ahead if they eat a banana with the common factor of their numerator and denominator on it.Which of the three monkeys will be able to reach the top.
Answers
Given : Three monkeys are climbing upstairs.
They can only move ahead if they eat a banana with the common factor of their numerator and denominator on it.
To Find : Which of the three monkeys will be able to reach the top.
Solution:
136 = 2 * 2 * 2 * 17
-124 = -1 * 2 * 2 * 31
Common factors are 2 or 4 only
can not eat 9 and 17
-112 = -1 * 2 * 2 * 2 * 2 * 7
224 = 2 * 2 * 2 * 2 * 2 * 7
1 , 2 , 7 , 2 are common factors
can eat all bananas
Hence monkey on left bottom picture will able to reach at top
- 108 = - 1 * 2 * 2 * 3 * 3 * 3
405 = 3 * 3 * 5 * 7
Common factor can be 1 , 3 and 9 only
Hence can not eat 4
-112 / 224 monkey can reach at TOP
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question-
Three monkeys are climbing upstairs.They can only move ahead if they eat a banana with the common factor of their numerator and denominator on it.Which of the three monkeys will be able to reach the top.
Answer-
a) 136= 2x2x2x17
-124= -1x2x2x31
common factors= 2 and 4
can not eat = 9 and 17
b) -112= -1x2x2x2x2x7
224= 2x2x2x2x2x7
common factor= 1,2,7 and 2
can eat all banana
c) -108= -1x2x2x3x3x3
405=3x3x5x7
common factor= 1,3and 9
can not eat= 9
hence,
-112 monkey can reach at the top
224