Question

Three number are in ratio 2:3:5. The sum of their cubes is 54880.find the number

Answer 1

let the common ratio=x
therefore 1st no.=2x
2 no=3x
3rd no.=5x

ATQ
(2x)^3 + (3x)^3+(5x)^3=54880
8x^3+27x^3+125x^3=54880
160x^3=54880
x^3=54880÷160
x^3=343
x=cube root 343
x=7


therefore
no.1=2×7=14
no.2=3×7=21
no.3=5×7=35

Answer 2

Answer:

let the common ratio =x

Step-by-step explanation:

therefore

1st no =2x

2no =3x

3rd =5x

(2x)³+(3x)³+(5x)³=54880

8x³+27x³+125x³ =5488

106x³=54880

x³=54880÷160

x³=343

x= cube root 343

x=7

the

therefore

number one 1=2×7=14

number one 2=3×7=21

number one 3=5×7=35