Question

three number are in the ratio 3:4:5 . The sum of their cube is27000,then find the numbers​

Answer 1

Answer:

15,20,25

Step-by-step explanation:

let numbers be 3x, 4x, 5x

the sum of their cubes = 27000

• (3x)^3+(4x)^3+(5x)^3=27000
• 27x^3+64x^3+125x^3=27000
• 216x^3=27000
• x^3=27000/216
• x^3=125
• x= cube root 125.
• x=5
• 3x=3*5=15
• 4x=4*5=20
• 5x=5*5=25

Answer 2

Step-by-step explanation:

Let the three numbers are 3x, 4x, 5x so that their ratio is 3:4:5

As their sum of cubes is 27000

(3x)^3+(4x)^3+(5x)^3=27000(3x)

3

+(4x)

3

+(5x)

3

=27000

27x^3+64x^3+125x^2=2700027x

3

+64x

3

+125x

2

=27000

216x^3=27000216x

3

=27000

x^3=\frac{27000}{216}=125x

3

=

216

27000

=125

Taking cube root on both sides, we get

x=5x=5

3x=3\times 5=15, 4x=4\times 5=20, 5x=5\times 5=253x=3×5=15,4x=4×5=20,5x=5×5=25

Hence, the three numbers are 15, 20, 25

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