Question

Three number are in the ratio of 1:2:3 the sum of their cubes is 62208 find the number

Answer 1

This is the answer my friend

Answer 2

Let the constant be k
Then according to the question, we have
${k}^{3} + {(2k)}^{3} + {(3k)}^{3} = 62208$
${k}^{3} + 8 {k}^{3} + 27 {k}^{3} = 62208$
$36 {k}^{3} = 62208$
${k}^{3} = 1728$
$k = 12$
Hence the numbers are 12, 24 and 36