Question

Three numbers a, b, c are subject to the conditions
2a + 5b-4c = 0
and 9a - 3b - c= 0
Find the simplest ratio, in which the numbers a, b, c are.​

Answer 1

Answer:

hi I am a potent than that it was a b c to the instructions to to run it through the following is a

Answer 2

Answer:

The simplest ratio for a,b, and c is a : b : c = 1 : 2 : 3

Step-by-step explanation:

In the Question,

Given - 2a + 5b- 4c = 0 --------------- Eq.1

     and  9a - 3b - c = 0 ---------------Eq.2

Solving equation 1 and 2 we get,

⇒      2a + 5b - 4c = 0

⇒      -36a +12b +4c = 0

Adding both equation

 ⇒       -34a + 17b = 0

 ⇒         2a = b

 ⇒         a:b =1:2

Putting b = 2a in eq.1 we get,

⇒     2a + 10a - 4c = 0

⇒      12a = 4c

⇒        3a = c

⇒        a:c = 1:3

Combining both the ratio a:b and a:c

⇒ a : b : c = 1 : 2 : 3

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