Three numbers are in
a. p. the difference between the first and the last is 8 and the product of these two is 20. find the numbers.
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three number a-d , a,a+d
a-d -(a+d)= -2d=8
d=-4
(a-d)*(a+d)=a^2-b^2=20
a^2-16=20
a=+/-6
three numbers : 10,6,2 ignore -6 as difference between first and third should be posituve
a-d -(a+d)= -2d=8
d=-4
(a-d)*(a+d)=a^2-b^2=20
a^2-16=20
a=+/-6
three numbers : 10,6,2 ignore -6 as difference between first and third should be posituve
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